What is the integral from 2 to 3 of (x-2)^3 ?

The integral from 2 to 3 of (x-2)^3 is 1/4

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integral from 2 to 3 of (x-2)^3

\int_{2}^{3} (x - 2)^{3} d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{2}^{3} (x - 2)^{3} d x

Apply u-substitution

: \int_{0}^{1} u^{3} d u

= \int_{0}^{1} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{0}^{1}

= [\frac{u ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

sec^{2} (x) d y + csc (y) d x = 0, y (\frac{π}{4}) = 0

x \to \infty + lim (3 + \frac{2}{x})

x^{2} y^{^{''}} + 2 x y^{^{'}} - 6 y = x^{2} - 2

\frac{\partial}{\partial x} (d)

\frac{d}{d x} (e^{10})

What is the integral from 2 to 3 of (x-2)^3 ?
The integral from 2 to 3 of (x-2)^3 is 1/4