What is the derivative of 9/(2x+1) ?

The derivative of 9/(2x+1) is -(18)/((2x+1)^2)

What is the first derivative of 9/(2x+1) ?

The first derivative of 9/(2x+1) is -(18)/((2x+1)^2)

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\frac{d}{d x} (\frac{9}{2 x + 1})

- \frac{18}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{2 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 9 (- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2)

Simplify

9 (- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2) : - \frac{18}{( 2 x + 1 ) ^{2}}

= - \frac{18}{( 2 x + 1 ) ^{2}}

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cos (2 x), π

What is the derivative of 9/(2x+1) ?
The derivative of 9/(2x+1) is -(18)/((2x+1)^2)
What is the first derivative of 9/(2x+1) ?
The first derivative of 9/(2x+1) is -(18)/((2x+1)^2)