What is the integral from-1 to 0 of 1/(sqrt(1-x^2)) ?

The integral from-1 to 0 of 1/(sqrt(1-x^2)) is pi/2

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integral from-1 to 0 of 1/(sqrt(1-x^2))

\int_{- 1}^{0} \frac{1}{1 - x ^{2}} d x

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

\int_{- 1}^{0} \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= [arcsin (x)]_{- 1}^{0}

Compute the boundaries:

\frac{π}{2}

= \frac{π}{2}

f (x) = \frac{1}{2 x}, at x = 25

- \frac{6 x}{x ^{2} + 1}

\frac{d}{d x} (ln ((arcsin (x))^{2}))

\frac{140000}{x}

\int \frac{1}{x ^{2} - 3 x - 15} d x

What is the integral from-1 to 0 of 1/(sqrt(1-x^2)) ?
The integral from-1 to 0 of 1/(sqrt(1-x^2)) is pi/2