What is the derivative of tan(xdx) ?

The derivative of tan(xdx) is d(xsec^2(x)+tan(x))

What is the first derivative of tan(xdx) ?

The first derivative of tan(xdx) is d(xsec^2(x)+tan(x))

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\frac{d}{d x} (tan (x) d x)

d (x sec^{2} (x) + tan (x))

Solution steps

\frac{d}{d x} (tan (x) d x)

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (tan (x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = tan (x), g = x

= d (\frac{d}{d x} (tan (x)) x + \frac{d x}{d x} tan (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d x}{d x} = 1

= d (sec^{2} (x) x + 1 \cdot tan (x))

Simplify

= d (x sec^{2} (x) + tan (x))

\int e^{\frac{2 x}{5}} d x

\frac{1}{1 - x}, 20

\int 6 x y d x

\frac{d y}{d x}, (4 x + 4 y) 3 = 64 x^{3} + 64 y^{3}

f (x) = - 3 - 5 x^{2}, at x = 3

What is the derivative of tan(xdx) ?
The derivative of tan(xdx) is d(xsec^2(x)+tan(x))
What is the first derivative of tan(xdx) ?
The first derivative of tan(xdx) is d(xsec^2(x)+tan(x))