What is the limit as x approaches 0 of 1/(e^{2x)-1} ?

The limit as x approaches 0 of 1/(e^{2x)-1} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/(e^{2x)-1}

x \to 0 lim (\frac{1}{e ^{2 x} - 1})

diverges

Solution steps

x \to 0 lim (\frac{1}{e ^{2 x} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{e ^{2 x} - 1}) = \infty

x \to 0 - lim (\frac{1}{e ^{2 x} - 1}) = - \infty

= diverges

\int x cos (5 x^{2}) d x

x \to 2 lim (\frac{4 x}{x - 4})

\frac{d}{d x} (\frac{x + 2}{2 - x})

\frac{\partial}{\partial k} (ln (sin (\frac{x}{k})))

\int \frac{x ^{2}}{4 x ^{3} + 7} d x

What is the limit as x approaches 0 of 1/(e^{2x)-1} ?
The limit as x approaches 0 of 1/(e^{2x)-1} is diverges