What is the d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) ?

The d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) is ln^2(1+i)(1+i)^n+ln^2(1-i)(1-i)^n

What is the first d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) ?

The first d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) is ln^2(1+i)(1+i)^n+ln^2(1-i)(1-i)^n

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\frac{d}{d n} ((1 + i)^{n} ln (1 + i) + (1 - i)^{n} ln (1 - i))

ln^{2} (1 + i) (1 + i)^{n} + ln^{2} (1 - i) (1 - i)^{n}

Solution steps

\frac{d}{d n} ((1 + i)^{n} ln (1 + i) + (1 - i)^{n} ln (1 - i))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d n} ((1 + i)^{n} ln (1 + i)) + \frac{d}{d n} ((1 - i)^{n} ln (1 - i))

\frac{d}{d n} ((1 + i)^{n} ln (1 + i)) = ln^{2} (1 + i) (1 + i)^{n}

\frac{d}{d n} ((1 - i)^{n} ln (1 - i)) = ln^{2} (1 - i) (1 - i)^{n}

= ln^{2} (1 + i) (1 + i)^{n} + ln^{2} (1 - i) (1 - i)^{n}

x \to 5 + lim (- \frac{3}{2} x + \frac{7}{2})

f (x) = \frac{1}{6} x^{4} - 6 x^{2} + 1

cos (sin (x^{5}))

\frac{d}{d x} (9 x sin (π x))

x \to 1 lim (\frac{x ^{6} - 1}{x - 1})

What is the d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) ?
The d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) is ln^2(1+i)(1+i)^n+ln^2(1-i)(1-i)^n
What is the first d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) ?
The first d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i)) is ln^2(1+i)(1+i)^n+ln^2(1-i)(1-i)^n