What is the integral of 0.0025x-0.075 ?

The integral of 0.0025x-0.075 is 0.00125x^2-0.075x+C

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integral of 0.0025x-0.075

\int 0.0025 x - 0.075 d x

0.00125 x^{2} - 0.075 x + C

Solution steps

\int 0.0025 x - 0.075 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.0025 x d x - \int 0.075 d x

\int 0.0025 x d x = 0.00125 x^{2}

\int 0.075 d x = 0.075 x

= 0.00125 x^{2} - 0.075 x

Add a constant to the solution

= 0.00125 x^{2} - 0.075 x + C

x \to 3 π lim (csc (x))

y^{^{'}} - 6 y = 0, y (2) = 4

\frac{d}{d x} (A e^{- x})

(x^{7} + y^{7}) d x + 7 x y^{6} d y = 0

What is the integral of 0.0025x-0.075 ?
The integral of 0.0025x-0.075 is 0.00125x^2-0.075x+C