What is the derivative of (2.99*10^{16})/(r^2) ?

The derivative of (2.99*10^{16})/(r^2) is -(5.98E16)/(r^3)

What is the first derivative of (2.99*10^{16})/(r^2) ?

The first derivative of (2.99*10^{16})/(r^2) is -(5.98E16)/(r^3)

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derivative of

\frac{2.99 \cdot 1 0 ^{16}}{r ^{2}}

- \frac{5.98 E 16}{r ^{3}}

Solution steps

\frac{d}{d r} (\frac{2.99 \cdot 1 0 ^{16}}{r ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2.99 \cdot 1 0^{16} \frac{d}{d r} (\frac{1}{r ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2.99 \cdot 1 0^{16} \frac{d}{d r} (r^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2.99 \cdot 1 0^{16} (- 2 r^{- 2 - 1})

Simplify

2.99 \cdot 1 0^{16} (- 2 r^{- 2 - 1}) : - \frac{5.98 E 16}{r ^{3}}

= - \frac{5.98 E 16}{r ^{3}}

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What is the derivative of (2.99*10^{16})/(r^2) ?
The derivative of (2.99*10^{16})/(r^2) is -(5.98E16)/(r^3)
What is the first derivative of (2.99*10^{16})/(r^2) ?
The first derivative of (2.99*10^{16})/(r^2) is -(5.98E16)/(r^3)