What is the derivative of (2(1-x^2)/((1+x^2)^2)) ?

The derivative of (2(1-x^2)/((1+x^2)^2)) is -(4x(-x^2+3))/((x^2+1)^3)

What is the first derivative of (2(1-x^2)/((1+x^2)^2)) ?

The first derivative of (2(1-x^2)/((1+x^2)^2)) is -(4x(-x^2+3))/((x^2+1)^3)

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\frac{d}{d x} (\frac{2 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}})

- \frac{4 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1 - x ^{2}}{( 1 + x ^{2} ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( 1 - x ^{2} ) ( 1 + x ^{2} ) ^{2} - \frac{d}{d x} ( ( 1 + x ^{2} ) ^{2} ) ( 1 - x ^{2} )}{( ( 1 + x ^{2} ) ^{2} ) ^{2}}

\frac{d}{d x} (1 - x^{2}) = - 2 x

\frac{d}{d x} ((1 + x^{2})^{2}) = 4 x (1 + x^{2})

= 2 \cdot \frac{( - 2 x ) ( 1 + x ^{2} ) ^{2} - 4 x ( 1 + x ^{2} ) ( 1 - x ^{2} )}{( ( 1 + x ^{2} ) ^{2} ) ^{2}}

Simplify

2 \cdot \frac{( - 2 x ) ( 1 + x ^{2} ) ^{2} - 4 x ( 1 + x ^{2} ) ( 1 - x ^{2} )}{( ( 1 + x ^{2} ) ^{2} ) ^{2}} : - \frac{4 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}}

= - \frac{4 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}}

\int_{- 5}^{5} π (25 - x^{2}) d x

\int e^{x} e^{x + 1} d x

x \to 6 lim (\frac{x - 6}{∣ x - 6 ∣})

n = 1 \sum \infty \frac{n - 1}{n + 1}

f (x) = 7 x e^{x} csc (x)

What is the derivative of (2(1-x^2)/((1+x^2)^2)) ?
The derivative of (2(1-x^2)/((1+x^2)^2)) is -(4x(-x^2+3))/((x^2+1)^3)
What is the first derivative of (2(1-x^2)/((1+x^2)^2)) ?
The first derivative of (2(1-x^2)/((1+x^2)^2)) is -(4x(-x^2+3))/((x^2+1)^3)