What is the derivative of ln(x+x) ?

The derivative of ln(x+x) is 1/x+1

What is the first derivative of ln(x+x) ?

The first derivative of ln(x+x) is 1/x+1

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\frac{d}{d x} (ln (x) + x)

\frac{1}{x} + 1

Solution steps

\frac{d}{d x} (ln (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) + \frac{d x}{d x}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{x} + 1

f (t) = \frac{8 ^{8 t}}{t}

(- \frac{5}{6}, 0), (0, 6)

\int \frac{2}{( x + 1 ) ( x ^{2} + 1 )} d x

\frac{d}{d x} (5 x^{4} ln (x))

\int cos (\frac{2 x}{3}) d x

What is the derivative of ln(x+x) ?
The derivative of ln(x+x) is 1/x+1
What is the first derivative of ln(x+x) ?
The first derivative of ln(x+x) is 1/x+1