What is the derivative of 9/(6-x) ?

The derivative of 9/(6-x) is 9/((6-x)^2)

What is the first derivative of 9/(6-x) ?

The first derivative of 9/(6-x) is 9/((6-x)^2)

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\frac{d}{d x} (\frac{9}{6 - x})

\frac{9}{( 6 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{6 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{6 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((6 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 6 - x ) ^{2}} \frac{d}{d x} (6 - x)

= - \frac{1}{( 6 - x ) ^{2}} \frac{d}{d x} (6 - x)

\frac{d}{d x} (6 - x) = - 1

= 9 (- \frac{1}{( 6 - x ) ^{2}} (- 1))

Simplify

9 (- \frac{1}{( 6 - x ) ^{2}} (- 1)) : \frac{9}{( 6 - x ) ^{2}}

= \frac{9}{( 6 - x ) ^{2}}

\int 2 x^{3} + 3 d x

\int_{0}^{1} 0.2 e^{- 0.2 x} d x

\frac{d}{d x} (\frac{x + 1}{x})

\frac{d}{d y} ((\frac{1}{y ^{2}} - \frac{5}{y ^{4}}) (y + 9 y^{3}))

What is the derivative of 9/(6-x) ?
The derivative of 9/(6-x) is 9/((6-x)^2)
What is the first derivative of 9/(6-x) ?
The first derivative of 9/(6-x) is 9/((6-x)^2)