What is the tangent of y=sqrt(2x),(18,6) ?

The tangent of y=sqrt(2x),(18,6) is y= 1/6 x+3

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tangent of y=sqrt(2x),(18,6)

tangent of

y = 2 x, (18, 6)

y = \frac{1}{6} x + 3

Solution steps

Find the slope of

y = 2 x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = 2 x

(18, 6) : m = \frac{1}{6}

Find the line with slope m=

\frac{1}{6}

and passing through

(18, 6) : y = \frac{1}{6} x + 3

y = \frac{1}{6} x + 3

\frac{\partial}{\partial x} (\frac{y e ^{- \frac{y}{x}}}{x ^{2}})

\int - 6 y d y

\int \frac{x}{1 + cos ( x )} d x

\frac{d}{d x} (\frac{1}{x} + x^{2})

f (x) = \frac{x}{x - 3}

What is the tangent of y=sqrt(2x),(18,6) ?
The tangent of y=sqrt(2x),(18,6) is y= 1/6 x+3