What is the solution for y^'+y=5sin(2t) ?

The solution for y^'+y=5sin(2t) is y=-2cos(2t)+sin(2t)+(c_{1})/(e^t)

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y^'+y=5sin(2t)

y^{^{'}} + y = 5 sin (2 t)

y = - 2 cos (2 t) + sin (2 t) + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) + y = 5 sin (2 t)

Solve linear ODE:

y = - 2 cos (2 t) + sin (2 t) + \frac{c _{1}}{e ^{t}}

y = - 2 cos (2 t) + sin (2 t) + \frac{c _{1}}{e ^{t}}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x ^{3}})

\int \frac{8}{x} d x

x \to 0 lim (2 x^{x})

\frac{1}{10 x ^{\frac{9}{10}}}

5 arctan (x - 1 + x^{2})

What is the solution for y^'+y=5sin(2t) ?
The solution for y^'+y=5sin(2t) is y=-2cos(2t)+sin(2t)+(c_{1})/(e^t)