What is (\partial)/(\partial x)(z^2y^2-e^x) ?

The answer to (\partial)/(\partial x)(z^2y^2-e^x) is -e^x

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(\partial)/(\partial x)(z^2y^2-e^x)

\frac{\partial}{\partial x} (z^{2} y^{2} - e^{x})

- e^{x}

Solution steps

\frac{\partial}{\partial x} (z^{2} y^{2} - e^{x})

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (z^{2} y^{2}) - \frac{\partial}{\partial x} (e^{x})

\frac{\partial}{\partial x} (z^{2} y^{2}) = 0

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 0 - e^{x}

Simplify

= - e^{x}

\int \frac{26}{( 169 x ^{2} + 1 ) ^{2}} d x

\frac{\partial}{\partial y} (\frac{y}{x ^{2} - y ^{2}})

\int_{0}^{1} \frac{5 x}{( 4 + x ^{2} ) ^{2}} d x

\int_{1}^{\infty} x^{- 1} d x

f (x) = \frac{1}{x - 2}, (1, - 1)

What is (\partial)/(\partial x)(z^2y^2-e^x) ?
The answer to (\partial)/(\partial x)(z^2y^2-e^x) is -e^x