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Popular >

derivative of \sqrt[4]{x}+1/(x^4)

Solution

derivative of

Solution

\frac{x ^{5} - 16 x ^{\frac{3}{4}}}{4 x ^{\frac{23}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{1}{x ^{4}}) = - \frac{4}{x ^{5}}

= \frac{1}{4 x ^{\frac{3}{4}}} - \frac{4}{x ^{5}}

Simplify

\frac{1}{4 x ^{\frac{3}{4}}} - \frac{4}{x ^{5}} : \frac{x ^{5} - 16 x ^{\frac{3}{4}}}{4 x ^{\frac{23}{4}}}

= \frac{x ^{5} - 16 x ^{\frac{3}{4}}}{4 x ^{\frac{23}{4}}}

Popular Examples

integral of sin(7x)sin(4x)

\int sin (7 x) sin (4 x) d x

tangent of f(x)=6x^2+8x-15,\at x=2 tangent of

f (x) = 6 x^{2} + 8 x - 15, at x = 2

(\partial)/(\partial y)(e^{-x^2-y^2})

\frac{\partial}{\partial y} (e^{- x^{2} - y^{2}})

limit as x approaches 3 of (tan(x-3))/(3e^{x-3)-x}

x \to 3 lim (\frac{tan ( x - 3 )}{3 e ^{x - 3} - x})

derivative of 1/(x^2+4)derivative of

\frac{1}{x ^{2} + 4}

Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[4]{x}+1/(x^4) ?
The derivative of \sqrt[4]{x}+1/(x^4) is (x^5-16x^{3/4})/(4x^{23/4)}
What is the first derivative of \sqrt[4]{x}+1/(x^4) ?
The first derivative of \sqrt[4]{x}+1/(x^4) is (x^5-16x^{3/4})/(4x^{23/4)}