What is area 9x^2,8x^4-8x^2 ?

The answer to area 9x^2,8x^4-8x^2 is (289sqrt(17))/(60sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 9x^2,8x^4-8x^2

area

9 x^{2}, 8 x^{4} - 8 x^{2}

\frac{289 17}{60 2}

Decimal Notation

14.04287 \dots

Solution steps

Apply the area formula:

\int_{- \frac{17}{2 2}}^{\frac{17}{2 2}} 9 x^{2} - (8 x^{4} - 8 x^{2}) d x

Solve

\int_{- \frac{17}{2 2}}^{\frac{17}{2 2}} 9 x^{2} - (8 x^{4} - 8 x^{2}) d x : \frac{289 17}{60 2}

The area is:

= \frac{289 17}{60 2}

\frac{d y}{d x} + 2 x^{2} = 0

\int \frac{e ^{x}}{e ^{x} + 6} d x

x e^{- \frac{1}{x}}

x (e^{\frac{y}{x}} - 1) \frac{d y}{d x} = e^{\frac{y}{x}} (y - x)

\frac{d}{d x} (\frac{e ^{x}}{7 x ^{3}})

What is area 9x^2,8x^4-8x^2 ?
The answer to area 9x^2,8x^4-8x^2 is (289sqrt(17))/(60sqrt(2))