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Popular >

y^'= y/x+(y/x)^2

Solution

y^{^{'}} = \frac{y}{x} + (\frac{y}{x})^{2}

Solution

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

y^{'} (x) = \frac{y}{x} + (\frac{y}{x})^{2}

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'= y/x+(y/x)^2 ?
The solution for y^'= y/x+(y/x)^2 is y= x/(-ln(x)+c_{1)}