What is the first derivative of y=x+5 ?

The first derivative of y=x+5 is 1

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derivative of y=x+5

derivative of

y = x + 5

1

Solution steps

\frac{d}{d x} (x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 1 + 0

Simplify

= 1

ln (2 e^{x} - e^{2 x})

\int \frac{x ^{8}}{( 2 - x ^{9} ) ^{2}} d x

x (\frac{d y}{d x}) - y = x^{2} sin (x)

y d x + (x - 1) d y = 0, y (2) = 9

y = \frac{x ^{2} + 8 x + 3}{x}