What is the solution for (dy)/(dx)=(2y)/(2x+1),y(0)=e ?

The solution for (dy)/(dx)=(2y)/(2x+1),y(0)=e is y=2ex+e

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(dy)/(dx)=(2y)/(2x+1),y(0)=e

\frac{d y}{d x} = \frac{2 y}{2 x + 1}, y (0) = e

y = 2 e x + e

Solution steps

\frac{d y}{d x} = \frac{2 y}{2 x + 1}

Solve separable ODE:

y = 2 e x + e

y = 2 e x + e

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What is the solution for (dy)/(dx)=(2y)/(2x+1),y(0)=e ?
The solution for (dy)/(dx)=(2y)/(2x+1),y(0)=e is y=2ex+e