What is the tangent of f(x)=(9x)/((x+1)^2),(0,0) ?

The tangent of f(x)=(9x)/((x+1)^2),(0,0) is y=9x

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tangent of f(x)=(9x)/((x+1)^2),(0,0)

tangent of

f (x) = \frac{9 x}{( x + 1 ) ^{2}}, (0, 0)

y = 9 x

Solution steps

Find the slope of

f (x) = \frac{9 x}{( x + 1 ) ^{2}} : \frac{df ( x )}{d x} = \frac{9 ( 1 - x )}{( x + 1 ) ^{3}}

Compute the slope of

f (x) = \frac{9 x}{( x + 1 ) ^{2}}

(0, 0) : m = 9

Find the line with slope m=

9

and passing through

(0, 0) : y = 9 x

y = 9 x

\frac{1}{s ( s ^{2} + 4 )}

\frac{d}{d x} (x ln (x + 2 y))

\frac{d}{d t} (t^{3} - t)

\frac{d y}{d x} = x x - 15

\frac{6}{s} + 8 a \frac{1}{s ^{2} + 16}

What is the tangent of f(x)=(9x)/((x+1)^2),(0,0) ?
The tangent of f(x)=(9x)/((x+1)^2),(0,0) is y=9x