What is the derivative of-1/((1+x^2)) ?

The derivative of-1/((1+x^2)) is 2/((1+x)^3)

What is the first derivative of-1/((1+x^2)) ?

The first derivative of-1/((1+x^2)) is 2/((1+x)^3)

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\frac{d}{d x} (- \frac{1}{( 1 + x ) ^{2}})

\frac{2}{( 1 + x ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{1}{( 1 + x ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{1}{( 1 + x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d x} ((1 + x)^{- 2})

Apply the chain rule:

- \frac{2}{( 1 + x ) ^{3}} \frac{d}{d x} (1 + x)

= - \frac{2}{( 1 + x ) ^{3}} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= - (- \frac{2}{( 1 + x ) ^{3}} \cdot 1)

Simplify

= \frac{2}{( 1 + x ) ^{3}}

\frac{\partial}{\partial x} (2 x y)

f (x) = (9 - 6 x^{2})^{2}

(2 x + y + 1) y^{^{'}} = 1

(x^{2} - 1)^{^{'}}

\frac{d}{d x} f (x) = - 9

What is the derivative of-1/((1+x^2)) ?
The derivative of-1/((1+x^2)) is 2/((1+x)^3)
What is the first derivative of-1/((1+x^2)) ?
The first derivative of-1/((1+x^2)) is 2/((1+x)^3)