What is the limit as x approaches 0 of 4/(sqrt(x)) ?

The limit as x approaches 0 of 4/(sqrt(x)) is diverges

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limit as x approaches 0 of 4/(sqrt(x))

x \to 0 lim (\frac{4}{x})

diverges

Solution steps

x \to 0 lim (\frac{4}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{4}{x}) = \infty

x \to 0 - lim (\frac{4}{x}) =

Undefined

= diverges

t y^{^{'}} - 4 y = t^{6} e^{t}

\frac{11}{( 9 x + 11 ) ^{2}}

\frac{\partial}{\partial x} (\frac{y}{( y + x ) ^{2}})

\frac{d}{d x} (x e^{4 x} + cos (2 x))

\frac{d y}{d x} = y^{2} - 16

What is the limit as x approaches 0 of 4/(sqrt(x)) ?
The limit as x approaches 0 of 4/(sqrt(x)) is diverges