What is the derivative of f(x)=x(x^3-8) ?

The derivative of f(x)=x(x^3-8) is 4x^3-8

What is the first derivative of f(x)=x(x^3-8) ?

The first derivative of f(x)=x(x^3-8) is 4x^3-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x (x^{3} - 8)

4 x^{3} - 8

Solution steps

\frac{d}{d x} (x (x^{3} - 8))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x^{3} - 8

= \frac{d x}{d x} (x^{3} - 8) + \frac{d}{d x} (x^{3} - 8) x

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{3} - 8) = 3 x^{2}

= 1 \cdot (x^{3} - 8) + 3 x^{2} x

Simplify

1 \cdot (x^{3} - 8) + 3 x^{2} x : 4 x^{3} - 8

= 4 x^{3} - 8

\frac{d y}{d x} = (1 - x) y^{2}

\int \frac{1}{2 ( 1 + x ) ^{2}} d x

\frac{s}{( s ^{2} + 1 )}

y^{^{'}} = y cos (2 x), y (0) = 1.6

y = (\frac{x ^{2} + 1}{x ^{2} - 1})^{3}

What is the derivative of f(x)=x(x^3-8) ?
The derivative of f(x)=x(x^3-8) is 4x^3-8
What is the first derivative of f(x)=x(x^3-8) ?
The first derivative of f(x)=x(x^3-8) is 4x^3-8