What is the solution for (dy}{dx}-(4y)/x =\frac{y^4)/(x^2) ?

The solution for (dy}{dx}-(4y)/x =\frac{y^4)/(x^2) is y=(\sqrt[3]{11}x^4)/(\sqrt[3]{-3x^{11)+c_{1}}}

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(dy}{dx}-(4y)/x =\frac{y^4)/(x^2)

\frac{d y}{d x} - \frac{4 y}{x} = \frac{y ^{4}}{x ^{2}}

Solution steps

\frac{d y}{d x} - \frac{4 y}{x} = \frac{y ^{4}}{x ^{2}}

Solve Bernoulli ODE:

\frac{\partial}{\partial x} (x e^{(\frac{x}{y})})

f (x) = (\frac{x}{2})^{4}

f (x) = (x - 1)^{\frac{2}{3}}

n = 0 \sum \infty x^{4 n}

\frac{d}{d x} (3 y x y)

What is the solution for (dy}{dx}-(4y)/x =\frac{y^4)/(x^2) ?
The solution for (dy}{dx}-(4y)/x =\frac{y^4)/(x^2) is y=(\sqrt[3]{11}x^4)/(\sqrt[3]{-3x^{11)+c_{1}}}