What is the solution for t(dy)/(dt)=t^3+20t^3y ?

The solution for t(dy)/(dt)=t^3+20t^3y is y=(e^{(20t^3+c_{1})/3})/(20)-1/20

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t(dy)/(dt)=t^3+20t^3y

t \frac{d y}{d t} = t^{3} + 20 t^{3} y

y = \frac{e ^{\frac{20 t ^{3} + c _{1}}{3}}}{20} - \frac{1}{20}

Solution steps

t \frac{d y}{d t} = t^{3} + 20 t^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{20 t ^{3} + c _{1}}{3}}}{20} - \frac{1}{20}

y = \frac{e ^{\frac{20 t ^{3} + c _{1}}{3}}}{20} - \frac{1}{20}

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f (x) = x^{\frac{1}{6}}

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What is the solution for t(dy)/(dt)=t^3+20t^3y ?
The solution for t(dy)/(dt)=t^3+20t^3y is y=(e^{(20t^3+c_{1})/3})/(20)-1/20