What is the derivative of 6x^2+8x+6 ?

The derivative of 6x^2+8x+6 is 12x+8

What is the first derivative of 6x^2+8x+6 ?

The first derivative of 6x^2+8x+6 is 12x+8

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\frac{d}{d x} (6 x^{2} + 8 x + 6)

12 x + 8

Solution steps

\frac{d}{d x} (6 x^{2} + 8 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (6)

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (6) = 0

= 12 x + 8 + 0

Simplify

= 12 x + 8

\int x^{15} e^{- x^{8}} d x

\int (2 x + 5) (x^{2} + 5 x)^{7} d x

\frac{d y}{d x} = \frac{13 x y}{( ln ( y ) ) ^{10}}

\frac{d h}{d t} = - h, h (0) = 0

y^{^{'}} = \frac{5 y}{x + 3}

What is the derivative of 6x^2+8x+6 ?
The derivative of 6x^2+8x+6 is 12x+8
What is the first derivative of 6x^2+8x+6 ?
The first derivative of 6x^2+8x+6 is 12x+8