What is the solution for y^{''}+3y=5 ?

The solution for y^{''}+3y=5 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)+5/3

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y^{''}+3y=5

y^{^{''}} + 3 y = 5

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{5}{3}

Solution steps

y^{''} (t) + 3 y = 5

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{5}{3}

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{5}{3}

y^{^{''}} + y = \frac{1}{2 k ^{2}} (1 + cos (2 t))

\frac{d}{d x} ((x^{5} + 1)^{4})

f (x) = \frac{1}{x}, at x = 81

arccos (x) + x, at x = 0

y = 9 + 5 x^{2} - 2 x^{3}

What is the solution for y^{''}+3y=5 ?
The solution for y^{''}+3y=5 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)+5/3