What is the derivative of 3+ln(x) ?

The derivative of 3+ln(x) is 1/x

What is the first derivative of 3+ln(x) ?

The first derivative of 3+ln(x) is 1/x

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\frac{d}{d x} (3 + ln (x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (3 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (3) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

\frac{e ^{- 7 s}}{s ^{2}}

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\int 13 tan^{5} (x) sec^{4} (x) d x

x \to 5 - lim (\frac{x + 1}{x + 5})

What is the derivative of 3+ln(x) ?
The derivative of 3+ln(x) is 1/x
What is the first derivative of 3+ln(x) ?
The first derivative of 3+ln(x) is 1/x