What is the derivative of f(x)=(ln(x^5))^2 ?

The derivative of f(x)=(ln(x^5))^2 is (10ln(x^5))/x

What is the first derivative of f(x)=(ln(x^5))^2 ?

The first derivative of f(x)=(ln(x^5))^2 is (10ln(x^5))/x

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derivative of

f (x) = (ln (x^{5}))^{2}

\frac{10 ln ( x ^{5} )}{x}

Solution steps

\frac{d}{d x} ((ln (x^{5}))^{2})

Apply the chain rule:

2 ln (x^{5}) \frac{d}{d x} (ln (x^{5}))

= 2 ln (x^{5}) \frac{d}{d x} (ln (x^{5}))

\frac{d}{d x} (ln (x^{5})) = \frac{5}{x}

= 2 ln (x^{5}) \frac{5}{x}

Simplify

2 ln (x^{5}) \frac{5}{x} : \frac{10 ln ( x ^{5} )}{x}

= \frac{10 ln ( x ^{5} )}{x}

\frac{d}{d x} (- \frac{1}{2} x cos (x))

\int \frac{9}{x ^{- 1} + 3} d x

\frac{\partial}{\partial x} (y cos (x^{2} y))

(8 \frac{1}{7}, 9), (4, 3 \frac{1}{5})

y = ln (x^{2} - 5 x + 1), (5, 0)

What is the derivative of f(x)=(ln(x^5))^2 ?
The derivative of f(x)=(ln(x^5))^2 is (10ln(x^5))/x
What is the first derivative of f(x)=(ln(x^5))^2 ?
The first derivative of f(x)=(ln(x^5))^2 is (10ln(x^5))/x