What is the integral of (2x)/(x+3) ?

The integral of (2x)/(x+3) is 2(x+3-3ln|x+3|)+C

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integral of (2x)/(x+3)

\int \frac{2 x}{x + 3} d x

2 (x + 3 - 3 ln ∣ x + 3 ∣) + C

Solution steps

\int \frac{2 x}{x + 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{x}{x + 3} d x

Apply u-substitution

: \int \frac{u - 3}{u} d u

= 2 \cdot \int \frac{u - 3}{u} d u

Expand

\frac{u - 3}{u} : 1 - \frac{3}{u}

= 2 \cdot \int 1 - \frac{3}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int 1 d u - \int \frac{3}{u} d u)

\int 1 d u = u

\int \frac{3}{u} d u = 3 ln ∣ u ∣

= 2 (u - 3 ln ∣ u ∣)

Substitute back

u = x + 3

= 2 (x + 3 - 3 ln ∣ x + 3 ∣)

Add a constant to the solution

= 2 (x + 3 - 3 ln ∣ x + 3 ∣) + C

\frac{d}{d x} (ln (\frac{5 x ^{3} sin ( - 5 x )}{3 - x}))

\int_{- 1}^{2} (x - 2 ∣ x ∣) d x

\int \frac{3 x ^{2} + 8}{x ^{3} + 8 x} d x

\int (\frac{1}{x} + 2 y^{2} x) d x

y = 9 - x^{2}

What is the integral of (2x)/(x+3) ?
The integral of (2x)/(x+3) is 2(x+3-3ln|x+3|)+C