What is the derivative of-x^2+x+a ?

The derivative of-x^2+x+a is -2x+1

What is the first derivative of-x^2+x+a ?

The first derivative of-x^2+x+a is -2x+1

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derivative of

- x^{2} + x + a

- 2 x + 1

Solution steps

\frac{d}{d x} (- x^{2} + x + a)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d a}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d a}{d x} = 0

= - 2 x + 1 + 0

Simplify

= - 2 x + 1

\frac{d}{d x} (8 x^{5} + 45 x^{4} + 80 x^{3} + 50 x^{2} + 200)

e^{t} cos (t)

(x - 6) y^{^{'}} + y = x^{2} - 20

\int x^{3} 16 - x^{2} d x

\int 8 x - 10 y + 2 d y

What is the derivative of-x^2+x+a ?
The derivative of-x^2+x+a is -2x+1
What is the first derivative of-x^2+x+a ?
The first derivative of-x^2+x+a is -2x+1