What is the solution for y^'=((1-2t))/y ?

The solution for y^'=((1-2t))/y is y=sqrt(2t-2t^2+c_{1)},y=-sqrt(2t-2t^2+c_{1)}

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y^'=((1-2t))/y

y^{^{'}} = \frac{( 1 - 2 t )}{y}

y = 2 t - 2 t^{2} + c_{1}, y = - 2 t - 2 t^{2} + c_{1}

Solution steps

y^{'} (t) = \frac{( 1 - 2 t )}{y}

Solve separable ODE:

y = 2 t - 2 t^{2} + c_{1}, y = - 2 t - 2 t^{2} + c_{1}

y = 2 t - 2 t^{2} + c_{1}, y = - 2 t - 2 t^{2} + c_{1}

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What is the solution for y^'=((1-2t))/y ?
The solution for y^'=((1-2t))/y is y=sqrt(2t-2t^2+c_{1)},y=-sqrt(2t-2t^2+c_{1)}