What is area y=2sqrt(x),y=((x^2))/4 ?

The answer to area y=2sqrt(x),y=((x^2))/4 is 16/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=2sqrt(x),y=((x^2))/4

area

y = 2 x, y = \frac{( x ^{2} )}{4}

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 2 x - \frac{x ^{2}}{4} d x

Solve

\int_{0}^{4} 2 x - \frac{x ^{2}}{4} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

\int 5 x^{4} e^{4 x^{5}} d x

sin (t) - t cos (t)

\frac{d y}{d x}, y = x^{4}

ln (x + 5 + x^{2})

\frac{d}{d x} (\frac{- 4}{x})

What is area y=2sqrt(x),y=((x^2))/4 ?
The answer to area y=2sqrt(x),y=((x^2))/4 is 16/3