What is the integral from-5 to 0 of (2+sqrt(25-x^2)) ?

The integral from-5 to 0 of (2+sqrt(25-x^2)) is 10+(25pi)/4

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integral from-5 to 0 of (2+sqrt(25-x^2))

\int_{- 5}^{0} (2 + 25 - x^{2}) d x

10 + \frac{25 π}{4}

Decimal Notation

29.63495 \dots

Solution steps

\int_{- 5}^{0} 2 + 25 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{0} 2 d x + \int_{- 5}^{0} 25 - x^{2} d x

\int_{- 5}^{0} 2 d x = 10

\int_{- 5}^{0} 25 - x^{2} d x = \frac{25 π}{4}

= 10 + \frac{25 π}{4}

x^{2} y^{^{'}} + (2 x^{2} - x) y = x^{4}

\frac{\partial}{\partial y} (x^{2} - \frac{y}{4})

9

f (x) = \frac{8 x}{x ^{2} + 1}, at x = 0

\frac{d}{d x} (x (1 - 2 y))

What is the integral from-5 to 0 of (2+sqrt(25-x^2)) ?
The integral from-5 to 0 of (2+sqrt(25-x^2)) is 10+(25pi)/4