What is the derivative of f(x)= 2/(x+3) ?

The derivative of f(x)= 2/(x+3) is -2/((x+3)^2)

What is the first derivative of f(x)= 2/(x+3) ?

The first derivative of f(x)= 2/(x+3) is -2/((x+3)^2)

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derivative of

f (x) = \frac{2}{x + 3}

- \frac{2}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

= - \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= 2 (- \frac{1}{( x + 3 ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( x + 3 ) ^{2}} \cdot 1) : - \frac{2}{( x + 3 ) ^{2}}

= - \frac{2}{( x + 3 ) ^{2}}

\frac{\partial}{\partial y} (x^{y} ln (x))

\int_{0}^{34} x^{2} - 17 d x

\frac{\partial}{\partial y} (x y + 3 x - 2 y)

\int_{0}^{1} x^{2} + 2 d x

\int \frac{tan ( \frac{2}{x} )}{x ^{2}} d x

What is the derivative of f(x)= 2/(x+3) ?
The derivative of f(x)= 2/(x+3) is -2/((x+3)^2)
What is the first derivative of f(x)= 2/(x+3) ?
The first derivative of f(x)= 2/(x+3) is -2/((x+3)^2)