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Popular >

y^{''}-y^'=1

Solution

y^{^{''}} - y^{^{'}} = 1

Solution

y = c_{1} e^{t} + c_{2} - t

Solution steps

y^{''} (t) - y^{'} (t) = 1

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - t

y = c_{1} e^{t} + c_{2} - t

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\frac{d}{d x} (cos^{3} (x^{2} - 1))

limit as x approaches+0+of x^{2/x}

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=1 ?
The solution for y^{''}-y^'=1 is y=c_{1}e^t+c_{2}-t