What is the integral of 1/(x^{7/2)} ?

The integral of 1/(x^{7/2)} is -2/(5x^{5/2)}+C

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integral of 1/(x^{7/2)}

\int \frac{1}{x ^{\frac{7}{2}}} d x

- \frac{2}{5 x ^{\frac{5}{2}}} + C

Solution steps

\int \frac{1}{x ^{\frac{7}{2}}} d x

Apply the Power Rule

: - \frac{2}{5 x ^{\frac{5}{2}}}

= - \frac{2}{5 x ^{\frac{5}{2}}}

Add a constant to the solution

= - \frac{2}{5 x ^{\frac{5}{2}}} + C

\frac{d}{d x} ((f (x) (4 x))^{2} + 5)

6 x + y^{2} = 16, x = y

\frac{d}{d x} (3 a x^{4} - 4 a x^{3} - 5 b x^{2} + 7 c x)

\int (\frac{1}{x ^{- 3}} + x^{2} e^{3 x^{3}} - \frac{8}{x}) d x

y^{^{'}} + 6 y = e^{- t} - 6

What is the integral of 1/(x^{7/2)} ?
The integral of 1/(x^{7/2)} is -2/(5x^{5/2)}+C