What is the tangent of y=x^4+9x^2-x,(1,9) ?

The tangent of y=x^4+9x^2-x,(1,9) is y=21x-12

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tangent of y=x^4+9x^2-x,(1,9)

tangent of

y = x^{4} + 9 x^{2} - x, (1, 9)

y = 21 x - 12

Solution steps

Find the slope of

y = x^{4} + 9 x^{2} - x : \frac{d y}{d x} = 4 x^{3} + 18 x - 1

Compute the slope of

y = x^{4} + 9 x^{2} - x

(1, 9) : m = 21

Find the line with slope m=

21

and passing through

(1, 9) : y = 21 x - 12

y = 21 x - 12

\int_{1}^{e} \frac{ln ( z )}{z ^{2}} d z

\frac{d}{d x} (\frac{80}{1 + 0.32 x})

x \to 1 lim (e^{x - 1})

\frac{d}{d x} (- \frac{2}{2 x + 5})

f (x) = ln (4 x^{2} + 1)

What is the tangent of y=x^4+9x^2-x,(1,9) ?
The tangent of y=x^4+9x^2-x,(1,9) is y=21x-12