What is the derivative of 3x(x^2-2/x) ?

The derivative of 3x(x^2-2/x) is 9x^2

What is the first derivative of 3x(x^2-2/x) ?

The first derivative of 3x(x^2-2/x) is 9x^2

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\frac{d}{d x} (3 x (x^{2} - \frac{2}{x}))

9 x^{2}

Solution steps

\frac{d}{d x} (3 x (x^{2} - \frac{2}{x}))

Simplify

3 x (x^{2} - \frac{2}{x}) : 3 x^{3} - 6

= \frac{d}{d x} (3 x^{3} - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (6)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (6) = 0

= 9 x^{2} - 0

Simplify

= 9 x^{2}

sin (x) ln (cos (x))

x \to - 1 lim (3 x^{2} + \frac{4}{x ^{2}})

\int - 9 cot (x) ln (sin (x)) d x

\frac{d}{d x} (4 e^{3 x^{2}} sin (cos (2 x)))

What is the derivative of 3x(x^2-2/x) ?
The derivative of 3x(x^2-2/x) is 9x^2
What is the first derivative of 3x(x^2-2/x) ?
The first derivative of 3x(x^2-2/x) is 9x^2