What is the derivative of sin^2(x-cos(x)) ?

The derivative of sin^2(x-cos(x)) is sin(2x)+sin(x)

What is the first derivative of sin^2(x-cos(x)) ?

The first derivative of sin^2(x-cos(x)) is sin(2x)+sin(x)

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\frac{d}{d x} (sin^{2} (x) - cos (x))

sin (2 x) + sin (x)

Solution steps

\frac{d}{d x} (sin^{2} (x) - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin^{2} (x)) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

\frac{d}{d x} (cos (x)) = - sin (x)

= sin (2 x) - (- sin (x))

Simplify

= sin (2 x) + sin (x)

\frac{d}{d x} (\frac{x ^{2} ( e ^{x} + 5 )}{e ^{x} x})

\frac{d}{d x} (7^{x} + 7 cos (\frac{7 x}{2}))

x^{2} y^{^{''}} - x y^{^{'}} + y = 0

\int_{1}^{e^{5}} \frac{1}{x ( 1 + ln ( x ) )} d x

\int - sin^{4} (x) d x

What is the derivative of sin^2(x-cos(x)) ?
The derivative of sin^2(x-cos(x)) is sin(2x)+sin(x)
What is the first derivative of sin^2(x-cos(x)) ?
The first derivative of sin^2(x-cos(x)) is sin(2x)+sin(x)