What is the derivative of \sqrt[4]{u} ?

The derivative of \sqrt[4]{u} is 1/(4u^{3/4)}

What is the first derivative of \sqrt[4]{u} ?

The first derivative of \sqrt[4]{u} is 1/(4u^{3/4)}

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derivative of

\frac{1}{4 u ^{\frac{3}{4}}}

Solution steps

Apply radical rule:

= \frac{d}{d u} (u^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} u^{\frac{1}{4} - 1}

Simplify

\frac{1}{4} u^{\frac{1}{4} - 1} : \frac{1}{4 u ^{\frac{3}{4}}}

= \frac{1}{4 u ^{\frac{3}{4}}}

\frac{d y}{d t} = \frac{t}{y}

\int \frac{1}{x + x ^{\frac{1}{3}}} d x

\frac{d}{d x} (arctan (\frac{1 + x}{1 - x}))

f (x) = x^{3}, (- 2, - 8)

\int \frac{( 9 sin ( x ) + 4 sec ( x ) )}{tan ( x )} d x

What is the derivative of \sqrt[4]{u} ?
The derivative of \sqrt[4]{u} is 1/(4u^{3/4)}
What is the first derivative of \sqrt[4]{u} ?
The first derivative of \sqrt[4]{u} is 1/(4u^{3/4)}