What is the derivative of (e^x/(e^x+e^y)) ?

The derivative of (e^x/(e^x+e^y)) is (e^{x+y}-e^{x+y}\frac{dy)/(dx)}{(e^x+e^y)^2}

What is the first derivative of (e^x/(e^x+e^y)) ?

The first derivative of (e^x/(e^x+e^y)) is (e^{x+y}-e^{x+y}\frac{dy)/(dx)}{(e^x+e^y)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{y}})

\frac{e ^{x + y} - e ^{x + y} \frac{d y}{d x}}{( e ^{x} + e ^{y} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{y}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( e ^{x} + e ^{y} ) - \frac{d}{d x} ( e ^{x} + e ^{y} ) e ^{x}}{( e ^{x} + e ^{y} ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{x} + e^{y}) = e^{x} + e^{y} \frac{d y}{d x}

= \frac{e ^{x} ( e ^{x} + e ^{y} ) - ( e ^{x} + e ^{y} \frac{d y}{d x} ) e ^{x}}{( e ^{x} + e ^{y} ) ^{2}}

Expand

e^{x} (e^{x} + e^{y}) - (e^{x} + e^{y} \frac{d y}{d x}) e^{x} : e^{x + y} - e^{x + y} \frac{d y}{d x}

= \frac{e ^{x + y} - e ^{x + y} \frac{d y}{d x}}{( e ^{x} + e ^{y} ) ^{2}}

x \to - 2 lim (x)

\int \frac{x ^{2} + 1}{( x - 9 ) ( x - 8 ) ^{2}} d x

\frac{d}{d x} ((x^{2} + x) 3^{x})

\int_{- 8}^{18} \frac{1}{∣ 2 x ∣} d x

What is the derivative of (e^x/(e^x+e^y)) ?
The derivative of (e^x/(e^x+e^y)) is (e^{x+y}-e^{x+y}\frac{dy)/(dx)}{(e^x+e^y)^2}
What is the first derivative of (e^x/(e^x+e^y)) ?
The first derivative of (e^x/(e^x+e^y)) is (e^{x+y}-e^{x+y}\frac{dy)/(dx)}{(e^x+e^y)^2}