What is the integral of 2r(sin(θ))z^3 ?

The integral of 2r(sin(θ))z^3 is z^3r^2sin(θ)+C

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integral of 2r(sin(θ))z^3

\int 2 r (sin (θ)) z^{3}

z^{3} r^{2} sin (θ) + C

Solution steps

\int 2 r sin (θ) z^{3} d r

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 sin (θ) z^{3} \cdot \int r d r

Apply the Power Rule

: \frac{r ^{2}}{2}

= 2 sin (θ) z^{3} \frac{r ^{2}}{2}

Simplify

2 sin (θ) z^{3} \frac{r ^{2}}{2} : z^{3} r^{2} sin (θ)

= z^{3} r^{2} sin (θ)

Add a constant to the solution

= z^{3} r^{2} sin (θ) + C

x^{2}, x^{3}, 0, \frac{1}{4}

n = 1 \sum \infty \frac{1}{n 9 ^{n}}

x \to \infty lim (0. 5^{x})

\int \frac{lo g _{4} ( x )}{x} d x

x \to - 2 lim ((2 - x)^{2})

What is the integral of 2r(sin(θ))z^3 ?
The integral of 2r(sin(θ))z^3 is z^3r^2sin(θ)+C