What is the solution for 2x^2(dy)/(dx)+2xy=y^3 ?

The solution for 2x^2(dy)/(dx)+2xy=y^3 is y=sqrt((3x)/(1+3c_{1)x^3)},y=-sqrt((3x)/(1+3c_{1)x^3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2(dy)/(dx)+2xy=y^3

2 x^{2} \frac{d y}{d x} + 2 x y = y^{3}

y = \frac{3 x}{1 + 3 c _{1} x ^{3}}, y = - \frac{3 x}{1 + 3 c _{1} x ^{3}}

Solution steps

2 x^{2} \frac{d y}{d x} + 2 x y = y^{3}

Solve Bernoulli ODE:

y = \frac{3 x}{1 + 3 c _{1} x ^{3}}, y = - \frac{3 x}{1 + 3 c _{1} x ^{3}}

y = \frac{3 x}{1 + 3 c _{1} x ^{3}}, y = - \frac{3 x}{1 + 3 c _{1} x ^{3}}

\int 36 - 9 x^{2} d x

\frac{d}{d s} (\frac{1 - s ^{2}}{( s ^{2} + 1 ) ^{2}})

\int \frac{1}{3 ( x - 2 )} d x

x^{^{''}} + 2 x^{^{'}} + x = 0, x (0) = 2, x^{^{'}} (0) = 1

\frac{\partial}{\partial y} (4 - y^{2})

What is the solution for 2x^2(dy)/(dx)+2xy=y^3 ?
The solution for 2x^2(dy)/(dx)+2xy=y^3 is y=sqrt((3x)/(1+3c_{1)x^3)},y=-sqrt((3x)/(1+3c_{1)x^3)}