What is (\partial)/(\partial x)(cos(y+x)) ?

The answer to (\partial)/(\partial x)(cos(y+x)) is -sin(y+x)

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(\partial)/(\partial x)(cos(y+x))

\frac{\partial}{\partial x} (cos (y + x))

- sin (y + x)

Solution steps

\frac{\partial}{\partial x} (cos (y + x))

Treat

y

as a constant

Apply the chain rule:

- sin (y + x) \frac{\partial}{\partial x} (y + x)

= - sin (y + x) \frac{\partial}{\partial x} (y + x)

\frac{\partial}{\partial x} (y + x) = 1

= - sin (y + x) \cdot 1

Simplify

= - sin (y + x)

(\frac{x + 1}{x - 3})^{2}

\int_{0}^{\infty} x e^{- \frac{x}{a}} d x

\int_{0}^{N} e^{(- s t)} sin (3 t) d t

\int \frac{1}{7 x + 8} d x

(0.1 x^{2} - 4.2 x + 6.5)^{1.5}

What is (\partial)/(\partial x)(cos(y+x)) ?
The answer to (\partial)/(\partial x)(cos(y+x)) is -sin(y+x)