What is the derivative of y=((cos(x))/(1-sin(x)))^2 ?

The derivative of y=((cos(x))/(1-sin(x)))^2 is (2cos(x))/((1-sin(x))^2)

What is the first derivative of y=((cos(x))/(1-sin(x)))^2 ?

The first derivative of y=((cos(x))/(1-sin(x)))^2 is (2cos(x))/((1-sin(x))^2)

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derivative of

y = (\frac{cos ( x )}{1 - sin ( x )})^{2}

\frac{2 cos ( x )}{( 1 - sin ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} ((\frac{cos ( x )}{1 - sin ( x )})^{2})

Apply the chain rule:

2 \cdot \frac{cos ( x )}{1 - sin ( x )} \frac{d}{d x} (\frac{cos ( x )}{1 - sin ( x )})

= 2 \cdot \frac{cos ( x )}{1 - sin ( x )} \frac{d}{d x} (\frac{cos ( x )}{1 - sin ( x )})

\frac{d}{d x} (\frac{cos ( x )}{1 - sin ( x )}) = \frac{1}{1 - sin ( x )}

= 2 \cdot \frac{cos ( x )}{1 - sin ( x )} \cdot \frac{1}{1 - sin ( x )}

Simplify

2 \cdot \frac{cos ( x )}{1 - sin ( x )} \cdot \frac{1}{1 - sin ( x )} : \frac{2 cos ( x )}{( 1 - sin ( x ) ) ^{2}}

= \frac{2 cos ( x )}{( 1 - sin ( x ) ) ^{2}}

n = 1 \sum \infty \frac{1}{3 ^{n} + n ^{3}}

\int t^{- 2} e^{t} d t

(- 5, 2), (5, - 4)

\frac{d y}{d x} - \frac{x}{y} = 2 y

ln (1 + 4^{x})

What is the derivative of y=((cos(x))/(1-sin(x)))^2 ?
The derivative of y=((cos(x))/(1-sin(x)))^2 is (2cos(x))/((1-sin(x))^2)
What is the first derivative of y=((cos(x))/(1-sin(x)))^2 ?
The first derivative of y=((cos(x))/(1-sin(x)))^2 is (2cos(x))/((1-sin(x))^2)