What is (\partial)/(\partial y)(15x^2-9xy+25y^2) ?

The answer to (\partial)/(\partial y)(15x^2-9xy+25y^2) is 50y-9x

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(\partial)/(\partial y)(15x^2-9xy+25y^2)

\frac{\partial}{\partial y} (15 x^{2} - 9 x y + 25 y^{2})

50 y - 9 x

Solution steps

\frac{\partial}{\partial y} (15 x^{2} - 9 x y + 25 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (15 x^{2}) - \frac{\partial}{\partial y} (9 x y) + \frac{\partial}{\partial y} (25 y^{2})

\frac{\partial}{\partial y} (15 x^{2}) = 0

\frac{\partial}{\partial y} (9 x y) = 9 x

\frac{\partial}{\partial y} (25 y^{2}) = 50 y

= 0 - 9 x + 50 y

Simplify

= 50 y - 9 x

p (t) = 12 t e^{- \frac{t}{6}}

\int \frac{x + 1}{x ^{4} - 4 x ^{2}} d x

\int (\frac{y ^{2}}{2} - y tan (x)) d x

\frac{9}{s ( s ^{2} + 9 s + 9 )}

y = (1 + 2 x)^{2}, at x = 1

What is (\partial)/(\partial y)(15x^2-9xy+25y^2) ?
The answer to (\partial)/(\partial y)(15x^2-9xy+25y^2) is 50y-9x