What is the derivative of-2sin(3x) ?

The derivative of-2sin(3x) is -6cos(3x)

What is the first derivative of-2sin(3x) ?

The first derivative of-2sin(3x) is -6cos(3x)

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\frac{d}{d x} (- 2 sin (3 x))

- 6 cos (3 x)

Solution steps

\frac{d}{d x} (- 2 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 2 cos (3 x) \cdot 3

Simplify

= - 6 cos (3 x)

f (x) = \frac{5}{x}, at x = 9

\frac{d}{d x} (\frac{cos ( x )}{x ^{8}})

\frac{d}{d x} (\frac{1}{( 2 x + 3 ) ^{2}})

\int sin^{2} (x + 2) d x

What is the derivative of-2sin(3x) ?
The derivative of-2sin(3x) is -6cos(3x)
What is the first derivative of-2sin(3x) ?
The first derivative of-2sin(3x) is -6cos(3x)