What is (\partial)/(\partial x)(cos(y)sin(x)) ?

The answer to (\partial)/(\partial x)(cos(y)sin(x)) is cos(y)cos(x)

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(\partial)/(\partial x)(cos(y)sin(x))

\frac{\partial}{\partial x} (cos (y) sin (x))

cos (y) cos (x)

Solution steps

\frac{\partial}{\partial x} (cos (y) sin (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= cos (y) cos (x)

\frac{d}{d x} (\frac{x + 1}{x + 2})

\int \frac{1}{( 2 x + 5 )} d x

\frac{d}{d x} (\frac{1}{x ^{2}})

\int \frac{2}{1 + x ^{4}} d x

\frac{1}{6 x}

What is (\partial)/(\partial x)(cos(y)sin(x)) ?
The answer to (\partial)/(\partial x)(cos(y)sin(x)) is cos(y)cos(x)