What is the derivative of f(x)=sqrt(16-x^2) ?

The derivative of f(x)=sqrt(16-x^2) is -x/(sqrt(16-x^2))

What is the first derivative of f(x)=sqrt(16-x^2) ?

The first derivative of f(x)=sqrt(16-x^2) is -x/(sqrt(16-x^2))

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derivative of

f (x) = 16 - x^{2}

- \frac{x}{16 - x ^{2}}

Solution steps

\frac{d}{d x} (16 - x^{2})

Apply the chain rule:

\frac{1}{2 16 - x ^{2}} \frac{d}{d x} (16 - x^{2})

= \frac{1}{2 16 - x ^{2}} \frac{d}{d x} (16 - x^{2})

\frac{d}{d x} (16 - x^{2}) = - 2 x

= \frac{1}{2 16 - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 16 - x ^{2}} (- 2 x) : - \frac{x}{16 - x ^{2}}

= - \frac{x}{16 - x ^{2}}

(4 x)^{^{'}}

\int (5 x^{2} + 5 x + 3)^{4} (2 x + 1) d x

\int \frac{- x}{( x ^{2} + 1 )} d x

\frac{d}{d x} (x^{6} (x - 1)^{5})

\frac{1}{ln ( 1 + x )} - \frac{1}{x}

What is the derivative of f(x)=sqrt(16-x^2) ?
The derivative of f(x)=sqrt(16-x^2) is -x/(sqrt(16-x^2))
What is the first derivative of f(x)=sqrt(16-x^2) ?
The first derivative of f(x)=sqrt(16-x^2) is -x/(sqrt(16-x^2))